Integrand size = 21, antiderivative size = 158 \[ \int \cos ^4(c+d x) (a+b \sin (c+d x))^3 \, dx=\frac {3}{16} a \left (2 a^2+b^2\right ) x-\frac {b \left (17 a^2+4 b^2\right ) \cos ^5(c+d x)}{70 d}+\frac {3 a \left (2 a^2+b^2\right ) \cos (c+d x) \sin (c+d x)}{16 d}+\frac {a \left (2 a^2+b^2\right ) \cos ^3(c+d x) \sin (c+d x)}{8 d}-\frac {3 a b \cos ^5(c+d x) (a+b \sin (c+d x))}{14 d}-\frac {b \cos ^5(c+d x) (a+b \sin (c+d x))^2}{7 d} \]
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Time = 0.15 (sec) , antiderivative size = 158, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 5, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.238, Rules used = {2771, 2941, 2748, 2715, 8} \[ \int \cos ^4(c+d x) (a+b \sin (c+d x))^3 \, dx=-\frac {b \left (17 a^2+4 b^2\right ) \cos ^5(c+d x)}{70 d}+\frac {a \left (2 a^2+b^2\right ) \sin (c+d x) \cos ^3(c+d x)}{8 d}+\frac {3 a \left (2 a^2+b^2\right ) \sin (c+d x) \cos (c+d x)}{16 d}+\frac {3}{16} a x \left (2 a^2+b^2\right )-\frac {b \cos ^5(c+d x) (a+b \sin (c+d x))^2}{7 d}-\frac {3 a b \cos ^5(c+d x) (a+b \sin (c+d x))}{14 d} \]
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Rule 8
Rule 2715
Rule 2748
Rule 2771
Rule 2941
Rubi steps \begin{align*} \text {integral}& = -\frac {b \cos ^5(c+d x) (a+b \sin (c+d x))^2}{7 d}+\frac {1}{7} \int \cos ^4(c+d x) (a+b \sin (c+d x)) \left (7 a^2+2 b^2+9 a b \sin (c+d x)\right ) \, dx \\ & = -\frac {3 a b \cos ^5(c+d x) (a+b \sin (c+d x))}{14 d}-\frac {b \cos ^5(c+d x) (a+b \sin (c+d x))^2}{7 d}+\frac {1}{42} \int \cos ^4(c+d x) \left (21 a \left (2 a^2+b^2\right )+3 b \left (17 a^2+4 b^2\right ) \sin (c+d x)\right ) \, dx \\ & = -\frac {b \left (17 a^2+4 b^2\right ) \cos ^5(c+d x)}{70 d}-\frac {3 a b \cos ^5(c+d x) (a+b \sin (c+d x))}{14 d}-\frac {b \cos ^5(c+d x) (a+b \sin (c+d x))^2}{7 d}+\frac {1}{2} \left (a \left (2 a^2+b^2\right )\right ) \int \cos ^4(c+d x) \, dx \\ & = -\frac {b \left (17 a^2+4 b^2\right ) \cos ^5(c+d x)}{70 d}+\frac {a \left (2 a^2+b^2\right ) \cos ^3(c+d x) \sin (c+d x)}{8 d}-\frac {3 a b \cos ^5(c+d x) (a+b \sin (c+d x))}{14 d}-\frac {b \cos ^5(c+d x) (a+b \sin (c+d x))^2}{7 d}+\frac {1}{8} \left (3 a \left (2 a^2+b^2\right )\right ) \int \cos ^2(c+d x) \, dx \\ & = -\frac {b \left (17 a^2+4 b^2\right ) \cos ^5(c+d x)}{70 d}+\frac {3 a \left (2 a^2+b^2\right ) \cos (c+d x) \sin (c+d x)}{16 d}+\frac {a \left (2 a^2+b^2\right ) \cos ^3(c+d x) \sin (c+d x)}{8 d}-\frac {3 a b \cos ^5(c+d x) (a+b \sin (c+d x))}{14 d}-\frac {b \cos ^5(c+d x) (a+b \sin (c+d x))^2}{7 d}+\frac {1}{16} \left (3 a \left (2 a^2+b^2\right )\right ) \int 1 \, dx \\ & = \frac {3}{16} a \left (2 a^2+b^2\right ) x-\frac {b \left (17 a^2+4 b^2\right ) \cos ^5(c+d x)}{70 d}+\frac {3 a \left (2 a^2+b^2\right ) \cos (c+d x) \sin (c+d x)}{16 d}+\frac {a \left (2 a^2+b^2\right ) \cos ^3(c+d x) \sin (c+d x)}{8 d}-\frac {3 a b \cos ^5(c+d x) (a+b \sin (c+d x))}{14 d}-\frac {b \cos ^5(c+d x) (a+b \sin (c+d x))^2}{7 d} \\ \end{align*}
Time = 0.52 (sec) , antiderivative size = 182, normalized size of antiderivative = 1.15 \[ \int \cos ^4(c+d x) (a+b \sin (c+d x))^3 \, dx=\frac {840 a^3 c+420 a b^2 c+840 a^3 d x+420 a b^2 d x-105 b \left (8 a^2+b^2\right ) \cos (c+d x)-35 \left (12 a^2 b+b^3\right ) \cos (3 (c+d x))-84 a^2 b \cos (5 (c+d x))+7 b^3 \cos (5 (c+d x))+5 b^3 \cos (7 (c+d x))+560 a^3 \sin (2 (c+d x))+105 a b^2 \sin (2 (c+d x))+70 a^3 \sin (4 (c+d x))-105 a b^2 \sin (4 (c+d x))-35 a b^2 \sin (6 (c+d x))}{2240 d} \]
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Time = 1.50 (sec) , antiderivative size = 145, normalized size of antiderivative = 0.92
method | result | size |
derivativedivides | \(\frac {a^{3} \left (\frac {\left (\cos ^{3}\left (d x +c \right )+\frac {3 \cos \left (d x +c \right )}{2}\right ) \sin \left (d x +c \right )}{4}+\frac {3 d x}{8}+\frac {3 c}{8}\right )-\frac {3 a^{2} b \left (\cos ^{5}\left (d x +c \right )\right )}{5}+3 a \,b^{2} \left (-\frac {\left (\cos ^{5}\left (d x +c \right )\right ) \sin \left (d x +c \right )}{6}+\frac {\left (\cos ^{3}\left (d x +c \right )+\frac {3 \cos \left (d x +c \right )}{2}\right ) \sin \left (d x +c \right )}{24}+\frac {d x}{16}+\frac {c}{16}\right )+b^{3} \left (-\frac {\left (\cos ^{5}\left (d x +c \right )\right ) \left (\sin ^{2}\left (d x +c \right )\right )}{7}-\frac {2 \left (\cos ^{5}\left (d x +c \right )\right )}{35}\right )}{d}\) | \(145\) |
default | \(\frac {a^{3} \left (\frac {\left (\cos ^{3}\left (d x +c \right )+\frac {3 \cos \left (d x +c \right )}{2}\right ) \sin \left (d x +c \right )}{4}+\frac {3 d x}{8}+\frac {3 c}{8}\right )-\frac {3 a^{2} b \left (\cos ^{5}\left (d x +c \right )\right )}{5}+3 a \,b^{2} \left (-\frac {\left (\cos ^{5}\left (d x +c \right )\right ) \sin \left (d x +c \right )}{6}+\frac {\left (\cos ^{3}\left (d x +c \right )+\frac {3 \cos \left (d x +c \right )}{2}\right ) \sin \left (d x +c \right )}{24}+\frac {d x}{16}+\frac {c}{16}\right )+b^{3} \left (-\frac {\left (\cos ^{5}\left (d x +c \right )\right ) \left (\sin ^{2}\left (d x +c \right )\right )}{7}-\frac {2 \left (\cos ^{5}\left (d x +c \right )\right )}{35}\right )}{d}\) | \(145\) |
parallelrisch | \(\frac {\left (-420 a^{2} b -35 b^{3}\right ) \cos \left (3 d x +3 c \right )+\left (-84 a^{2} b +7 b^{3}\right ) \cos \left (5 d x +5 c \right )+\left (560 a^{3}+105 a \,b^{2}\right ) \sin \left (2 d x +2 c \right )+\left (70 a^{3}-105 a \,b^{2}\right ) \sin \left (4 d x +4 c \right )+5 b^{3} \cos \left (7 d x +7 c \right )-35 a \,b^{2} \sin \left (6 d x +6 c \right )+\left (-840 a^{2} b -105 b^{3}\right ) \cos \left (d x +c \right )+840 a^{3} d x +420 a \,b^{2} d x -1344 a^{2} b -128 b^{3}}{2240 d}\) | \(169\) |
risch | \(\frac {3 a^{3} x}{8}+\frac {3 a \,b^{2} x}{16}-\frac {3 b \cos \left (d x +c \right ) a^{2}}{8 d}-\frac {3 b^{3} \cos \left (d x +c \right )}{64 d}+\frac {b^{3} \cos \left (7 d x +7 c \right )}{448 d}-\frac {a \,b^{2} \sin \left (6 d x +6 c \right )}{64 d}-\frac {3 b \cos \left (5 d x +5 c \right ) a^{2}}{80 d}+\frac {b^{3} \cos \left (5 d x +5 c \right )}{320 d}+\frac {\sin \left (4 d x +4 c \right ) a^{3}}{32 d}-\frac {3 \sin \left (4 d x +4 c \right ) a \,b^{2}}{64 d}-\frac {3 b \cos \left (3 d x +3 c \right ) a^{2}}{16 d}-\frac {b^{3} \cos \left (3 d x +3 c \right )}{64 d}+\frac {\sin \left (2 d x +2 c \right ) a^{3}}{4 d}+\frac {3 \sin \left (2 d x +2 c \right ) a \,b^{2}}{64 d}\) | \(219\) |
norman | \(\frac {\left (\frac {3}{8} a^{3}+\frac {3}{16} a \,b^{2}\right ) x +\left (\frac {3}{8} a^{3}+\frac {3}{16} a \,b^{2}\right ) x \left (\tan ^{14}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )+\left (\frac {21}{8} a^{3}+\frac {21}{16} a \,b^{2}\right ) x \left (\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )+\left (\frac {21}{8} a^{3}+\frac {21}{16} a \,b^{2}\right ) x \left (\tan ^{12}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )+\left (\frac {63}{8} a^{3}+\frac {63}{16} a \,b^{2}\right ) x \left (\tan ^{4}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )+\left (\frac {63}{8} a^{3}+\frac {63}{16} a \,b^{2}\right ) x \left (\tan ^{10}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )+\left (\frac {105}{8} a^{3}+\frac {105}{16} a \,b^{2}\right ) x \left (\tan ^{6}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )+\left (\frac {105}{8} a^{3}+\frac {105}{16} a \,b^{2}\right ) x \left (\tan ^{8}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )-\frac {42 a^{2} b +4 b^{3}}{35 d}-\frac {6 a^{2} b \left (\tan ^{12}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{d}-\frac {\left (12 a^{2} b +4 b^{3}\right ) \left (\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{5 d}-\frac {\left (12 a^{2} b +4 b^{3}\right ) \left (\tan ^{10}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{d}-\frac {\left (18 a^{2} b -4 b^{3}\right ) \left (\tan ^{8}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{d}-\frac {\left (24 a^{2} b +8 b^{3}\right ) \left (\tan ^{6}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{d}-\frac {\left (66 a^{2} b -8 b^{3}\right ) \left (\tan ^{4}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{5 d}+\frac {a \left (6 a^{2}+11 b^{2}\right ) \left (\tan ^{3}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{2 d}-\frac {a \left (6 a^{2}+11 b^{2}\right ) \left (\tan ^{11}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{2 d}+\frac {a \left (10 a^{2}-3 b^{2}\right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )}{8 d}-\frac {a \left (10 a^{2}-3 b^{2}\right ) \left (\tan ^{13}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{8 d}+\frac {a \left (18 a^{2}-31 b^{2}\right ) \left (\tan ^{5}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{8 d}-\frac {a \left (18 a^{2}-31 b^{2}\right ) \left (\tan ^{9}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{8 d}}{\left (1+\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )^{7}}\) | \(550\) |
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Time = 0.30 (sec) , antiderivative size = 117, normalized size of antiderivative = 0.74 \[ \int \cos ^4(c+d x) (a+b \sin (c+d x))^3 \, dx=\frac {80 \, b^{3} \cos \left (d x + c\right )^{7} - 112 \, {\left (3 \, a^{2} b + b^{3}\right )} \cos \left (d x + c\right )^{5} + 105 \, {\left (2 \, a^{3} + a b^{2}\right )} d x - 35 \, {\left (8 \, a b^{2} \cos \left (d x + c\right )^{5} - 2 \, {\left (2 \, a^{3} + a b^{2}\right )} \cos \left (d x + c\right )^{3} - 3 \, {\left (2 \, a^{3} + a b^{2}\right )} \cos \left (d x + c\right )\right )} \sin \left (d x + c\right )}{560 \, d} \]
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Leaf count of result is larger than twice the leaf count of optimal. 348 vs. \(2 (148) = 296\).
Time = 0.51 (sec) , antiderivative size = 348, normalized size of antiderivative = 2.20 \[ \int \cos ^4(c+d x) (a+b \sin (c+d x))^3 \, dx=\begin {cases} \frac {3 a^{3} x \sin ^{4}{\left (c + d x \right )}}{8} + \frac {3 a^{3} x \sin ^{2}{\left (c + d x \right )} \cos ^{2}{\left (c + d x \right )}}{4} + \frac {3 a^{3} x \cos ^{4}{\left (c + d x \right )}}{8} + \frac {3 a^{3} \sin ^{3}{\left (c + d x \right )} \cos {\left (c + d x \right )}}{8 d} + \frac {5 a^{3} \sin {\left (c + d x \right )} \cos ^{3}{\left (c + d x \right )}}{8 d} - \frac {3 a^{2} b \cos ^{5}{\left (c + d x \right )}}{5 d} + \frac {3 a b^{2} x \sin ^{6}{\left (c + d x \right )}}{16} + \frac {9 a b^{2} x \sin ^{4}{\left (c + d x \right )} \cos ^{2}{\left (c + d x \right )}}{16} + \frac {9 a b^{2} x \sin ^{2}{\left (c + d x \right )} \cos ^{4}{\left (c + d x \right )}}{16} + \frac {3 a b^{2} x \cos ^{6}{\left (c + d x \right )}}{16} + \frac {3 a b^{2} \sin ^{5}{\left (c + d x \right )} \cos {\left (c + d x \right )}}{16 d} + \frac {a b^{2} \sin ^{3}{\left (c + d x \right )} \cos ^{3}{\left (c + d x \right )}}{2 d} - \frac {3 a b^{2} \sin {\left (c + d x \right )} \cos ^{5}{\left (c + d x \right )}}{16 d} - \frac {b^{3} \sin ^{2}{\left (c + d x \right )} \cos ^{5}{\left (c + d x \right )}}{5 d} - \frac {2 b^{3} \cos ^{7}{\left (c + d x \right )}}{35 d} & \text {for}\: d \neq 0 \\x \left (a + b \sin {\left (c \right )}\right )^{3} \cos ^{4}{\left (c \right )} & \text {otherwise} \end {cases} \]
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Time = 0.19 (sec) , antiderivative size = 117, normalized size of antiderivative = 0.74 \[ \int \cos ^4(c+d x) (a+b \sin (c+d x))^3 \, dx=-\frac {1344 \, a^{2} b \cos \left (d x + c\right )^{5} - 70 \, {\left (12 \, d x + 12 \, c + \sin \left (4 \, d x + 4 \, c\right ) + 8 \, \sin \left (2 \, d x + 2 \, c\right )\right )} a^{3} - 35 \, {\left (4 \, \sin \left (2 \, d x + 2 \, c\right )^{3} + 12 \, d x + 12 \, c - 3 \, \sin \left (4 \, d x + 4 \, c\right )\right )} a b^{2} - 64 \, {\left (5 \, \cos \left (d x + c\right )^{7} - 7 \, \cos \left (d x + c\right )^{5}\right )} b^{3}}{2240 \, d} \]
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Time = 0.61 (sec) , antiderivative size = 173, normalized size of antiderivative = 1.09 \[ \int \cos ^4(c+d x) (a+b \sin (c+d x))^3 \, dx=\frac {b^{3} \cos \left (7 \, d x + 7 \, c\right )}{448 \, d} - \frac {a b^{2} \sin \left (6 \, d x + 6 \, c\right )}{64 \, d} + \frac {3}{16} \, {\left (2 \, a^{3} + a b^{2}\right )} x - \frac {{\left (12 \, a^{2} b - b^{3}\right )} \cos \left (5 \, d x + 5 \, c\right )}{320 \, d} - \frac {{\left (12 \, a^{2} b + b^{3}\right )} \cos \left (3 \, d x + 3 \, c\right )}{64 \, d} - \frac {3 \, {\left (8 \, a^{2} b + b^{3}\right )} \cos \left (d x + c\right )}{64 \, d} + \frac {{\left (2 \, a^{3} - 3 \, a b^{2}\right )} \sin \left (4 \, d x + 4 \, c\right )}{64 \, d} + \frac {{\left (16 \, a^{3} + 3 \, a b^{2}\right )} \sin \left (2 \, d x + 2 \, c\right )}{64 \, d} \]
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Time = 5.90 (sec) , antiderivative size = 474, normalized size of antiderivative = 3.00 \[ \int \cos ^4(c+d x) (a+b \sin (c+d x))^3 \, dx=\frac {3\,a\,\mathrm {atan}\left (\frac {3\,a\,\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )\,\left (2\,a^2+b^2\right )}{8\,\left (\frac {3\,a^3}{4}+\frac {3\,a\,b^2}{8}\right )}\right )\,\left (2\,a^2+b^2\right )}{8\,d}-\frac {\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )\,\left (\frac {3\,a\,b^2}{8}-\frac {5\,a^3}{4}\right )+\frac {6\,a^2\,b}{5}-{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^3\,\left (3\,a^3+\frac {11\,a\,b^2}{2}\right )+{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^{11}\,\left (3\,a^3+\frac {11\,a\,b^2}{2}\right )-{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^{13}\,\left (\frac {3\,a\,b^2}{8}-\frac {5\,a^3}{4}\right )+{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^5\,\left (\frac {31\,a\,b^2}{8}-\frac {9\,a^3}{4}\right )-{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^9\,\left (\frac {31\,a\,b^2}{8}-\frac {9\,a^3}{4}\right )+{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^{10}\,\left (12\,a^2\,b+4\,b^3\right )+{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^2\,\left (\frac {12\,a^2\,b}{5}+\frac {4\,b^3}{5}\right )+{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^8\,\left (18\,a^2\,b-4\,b^3\right )+{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^6\,\left (24\,a^2\,b+8\,b^3\right )+{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^4\,\left (\frac {66\,a^2\,b}{5}-\frac {8\,b^3}{5}\right )+\frac {4\,b^3}{35}+6\,a^2\,b\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^{12}}{d\,\left ({\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^{14}+7\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^{12}+21\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^{10}+35\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^8+35\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^6+21\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^4+7\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^2+1\right )}-\frac {3\,a\,\left (2\,a^2+b^2\right )\,\left (\mathrm {atan}\left (\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )\right )-\frac {d\,x}{2}\right )}{8\,d} \]
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